Finite Math Examples

$f (x) = - 6 x + 7 e^{- 9 x}$ , $x - 1 = 1$

Step 1

Replace the variable $x$ with $1$ in the expression.

$f (1) = - 6 \cdot 1 + 7 e^{- 9 \cdot 1}$

Step 2

Simplify the result.

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Step 2.1

Simplify each term.

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Step 2.1.1

Multiply $- 6$ by $1$ .

$f (1) = - 6 + 7 e^{- 9 \cdot 1}$

Step 2.1.2

Multiply $- 9$ by $1$ .

$f (1) = - 6 + 7 e^{- 9}$

Step 2.1.3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f (1) = - 6 + 7 (\frac{1}{e^{9}})$

Step 2.1.4

Combine $7$ and $\frac{1}{e^{9}}$ .

$f (1) = - 6 + \frac{7}{e^{9}}$

Step 2.2

The final answer is $- 6 + \frac{7}{e^{9}}$ .

$- 6 + \frac{7}{e^{9}}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$- 6 + \frac{7}{e^{9}}$

Decimal Form:

$- 5.99913613 \dots$

Step 4